Factors:
We are aware that a natural number can be expressed as the product of other natural numbers. As
20 = 2 x 10 = 4 x 5
Thus, 1, 2, 4, 5, 10, 20 are the factors of 20. Of these 2 and 5 are prime factors of 20.
Similarly, there are factors of algebraic expressions as,
5ab = 5 x a x b where 5, a and b are prime factors of 5ab.
Factorisation:
When we factorise an algebraic expression, we write it as a product of factors. These factors may be numbers, algebraic variables or algebraic expressions.
Example: 12xy is already in factors but we write it as 3 x 2 x 2 x X x Y. thus factors are 2, 3, x, y.
Factorisation by Common Factors:
As the term common itself suggest that it must be some similar pattern.
A systematic way of factorising an expression is the common factor method. It consists of three steps:
- Write each term of the expression as a product of irreducible factors
- Look for and separate the common factors and
- Combine the remaining factors in each term in accordance with the distributive law.
As example: We have to factorise 3x + 9.
first let’s factorise 3x = 3 x X and 9 = 3 x 3
similar pattern (say common) among these factors of both are 3
thus we can write 3x + 9 = 3 x X + 3 x 3 = 3(x + 3)
Factorisation by regrouping terms:
Rearranging the expression allows us to form groups leading to factorisation. This is regrouping.
Let us write (2xy + 2y) in the factor form:
2xy + 2y = (2 × x × y) + (2 × y)
= (2 × y × x) + (2 × y × 1)
= (2y × x) + (2y × 1) = 2y (x + 1)
Factorisation using identities:
- (a + b)2 = a2 + 2ab + b2
- (a – b)2 = a2 – 2ab + b2
- (a + b) (a – b) = a2 – b2
Factors of the product form
- (x + a).(x + b) = x2 + (a + b) x + ab
Division:
We already know that division is the inverse of multiplication for numerals. It is also applicable to the division of algebraic expressions.
Division of a monomial by another monomial:
We use the simple method for division. The division of numerical is same as we divide but for the monomials, we simply subtract the power of denominator from the numerator.
Example: \(\frac{21x^{4}}{7x}\) = 3x2
Division of Algebraic Expressions Continued (Polynomial ÷ Polynomial):
By taking the common factor we divide it.
Just an example: (7x2 + 14x) ÷ (x + 2)
(7x2 + 14x) = (7 × x × x) + (2 × 7 × x) = 7x(x + 2)
thus, (7x2 + 14x) ÷ (x + 2)
= \(\frac{7x\:(x \:+ \:2)}{x \:+ \:2}\) = 7x
Examples related to factorisation:
- Factorise 12a2b + 15ab2.
Solution:
As, 12a2b = 2 × 2 × 3 × a × a × b
and, 15ab2 = 3 × 5 × a × b × b
by seeing the two terms we find that these two terms have 3, a and b as common factors.
12a2b + 15ab2 = (3 × a × b × 2 × 2 × a) + (3 × a × b × 5 × b)
= 3 × a × b × [(2 × 2 × a) + (5 × b)]
= 3ab × (4a + 5b)
= 3ab (4a + 5b) - Factorise 6xy – 4y + 6 – 9x.
Solution:
6xy – 4y = 2y (3x – 2)
–9x + 6 = –3 (3x) + 3 (2)
Taking them together,
6xy – 4y + 6 – 9x = 6xy – 4y – 9x + 6
= 2y (3x – 2) – 3 (3x – 2)
= (3x – 2) (2y – 3)
thus factors of (6xy – 4y + 6 – 9 x) are (3x – 2) and (2y – 3).
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